And so we can write that C value as 2 root 5. Because 4 times 5 is 20, but we know the square root of 4 is 2. And I'm not sure if you're okay with just the rounded answer or you need to break that down as 4 times 5. And then you have to square root both sides. A squared plus B squared equals C squared. I'm going to call it C because a lot of people do that. ![]() ii DE bisects and ADC and iii Angle DEC is a right angle. Solution: Given, ABCD is a parallelogram. So what's the Pythagorean theorem? It's a leg squared plus leg squared equals that distance squared. In parallelogram ABCD, E is the mid point of side AB and CE bisects angle BCD. Which brings me into part B, which you actually have to do the Pythagorean theorem to figure out what this distance is. I don't know if you have to write down the units, but it would be in square units. So f rom the given f igure, B D 6x+3y8 7y 6x4y 8 x 8+4y 6 (1) Also we know that adjacent angles in a parallelogram are supplementary. W e know that in a parallelogram opposite angles are equal. And the height is, you have a right angle in here, I forgot to draw that in, is 4. Solution Verified by Toppr Given that ABCD is a parallelogram. And I'm inferring from the directions that just from this point to this point, from A to D, is 12. The area of triangle EFG is equal to 6cm and DE EF 1/3 of CD. Well it's just equal to the base times the height. Find an answer to your question In the following figure, ABCD is a parallelogram. ![]() So the first question, part A, is the area of the ABCD, which is the parallelogram. That over here is 2, going straight up is 4. I think it's well drawn and it clues you in very well on what you're doing.
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